How much does a 4x8 sheet of 1/8 aluminum weigh?

To calculate the weight of a 4x8 foot sheet of 1/8 inch thick aluminum, we need to know the density of aluminum and how to convert the given dimensions to volume, and then multiply the volume by the density of aluminum to get the weight.

First, we need to convert the dimensions of the aluminum sheet from feet and inches to inches, since density is usually given as mass per cubic inch. The dimensions of the aluminum sheet are 4 feet x 8 feet x 1/8 inches.

1 foot = 12 inches
So, 4 feet = 4 × 12 = 48 inches
8 feet = 8 × 12 = 96 inches

The volume V of the aluminum sheet can be calculated using the following formula:
V = length × width × height
V = 48 inches × 96 inches × (1/8) inches
V = 48 × 96 × 0.125 = 576 cubic inches

Next, we need to know the density of aluminum. The density of aluminum is approximately 2.7 grams per cubic centimeter. However, to keep it consistent with our units, we need to convert it to grams per cubic inch.

We know that:
1 cubic centimeter = 0.61 cubic inches
So, the density of aluminum in grams per cubic inch is:
(2.7 grams per cubic centimeter) ÷ 0.61 = 4.43 grams per cubic inch (rounded to two decimal places)

Finally, we multiply the volume of the aluminum sheet by the density of the aluminum to get its weight:
Weight = Volume × Density
Weight = 576 cubic inches × 4.43 grams per cubic inch
Weight = 2556.48 grams

Converting grams to the more common unit of pounds, we know that:
1 pound ≈ 453.59 grams
So, the weight of the aluminum sheet is approximately:
2556.48 grams ÷ 453.59 ≈ 5.64 Pounds (rounded to 2 decimal places)

To put this into context, a 4x8 foot sheet of aluminum that is 1/8 inch thick weighs approximately 5.64 pounds.